Sine and Cosine Rule
Sine and Cosine Rule
How useful are sine and cosine rule
Everyone thinks that what is the use sine and cosine rule so we can understand in this blog that how sine and cosine rule helps in calculating the big calculation. Now let's start-
We can easily find the sides of a right triangle if one side and one angle is given in the question or in triangle.
But if the triangle is not right triangle then What's you do???
Now, we use sine and cosine rule to find the side of a triangle if the triangle is not right angled.
So let's start sine and cosine rule
In∆ABD
SinB=AD/AB
AD=cSinB —1
In ∆ACD
SinC=AD/AC
AD=bSinC —2
From equation 1 and 2, we get
cSinB=bSinC
➡️ c/SinC=b/SinB —3
And,
In ∆BAE
SinA=BE/AB
BE=cSinA —4
In ∆BCE
SinC=BE/BC
BE=aSinC —5
From equation 4 and 5, we get
➡️c/sinC=a/sinA —6
Now,from equation 3 and 6, we get
➡️ a/sinA=b/sinB=c/sinC
๐
This is Sine Rule
Cosine Rule
By using this rule we can also find the sides of a triangle if the triangle is not right angled.
So,let's start the derivation
In ∆ABD
AD²+x²=c²
AD²=c²-x² —1
In ∆ACD
AD²+(a-x)²=b²
AD²=b²-(a-x)² —2
Now, from equation 1 and 2, we get
c²-x²=b²-a²-x²+2ax
2ax=c²+a²-b²
2acCosB=a²+c²-b² (cosB=X/c then,X=cCosB)
➡️CosB=a²+c²-b²/2ac
๐
This is cosine Rule
We can find with any angle in a triangle
like,
CosA=b²+c²-a²/2bc,and
CosC=a²+b²-c²/2ab
THANKS


In ∆ACD
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